Find the discriminant of the following quadra | vedclass

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(B) The given quadratic equation is $\frac{1}{4} x^{2} - 2x + 1 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = \frac{1}{

Vedclass · Accepted Answer

Discriminant = $0$,Roots are real and equal

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(B) The given quadratic equation is $\frac{1}{4} x^{2} - 2x + 1 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = \frac{1}{4}$,$b = -2$,and $c = 1$.The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.Substituting the values: $D = (-2)^{2} - 4(\frac{1}{4})(1)$.$D = 4 - 1 = 3$.Since $D > 0$,the roots of the equation are real and distinct.

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $\frac{1}{4} x^{2} - 2x + 1 = 0$.

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